168k views
2 votes
Identify the vertical asymptote(s) of each function. Check all of the boxes that apply. f(x)=x-8/x^2-3x+2

x = -8


x = -2


x = -1


x = 1


x = 2


x = 8

Nevermind the answer was x=1 and x=2. If anyone is wondering how to do it you can put the denominator in desmos and where the 2 points hit the x axis is your answer.

User Gil Fink
by
7.4k points

2 Answers

3 votes
Nevermind the answer was x=1 and x=2. If anyone is wondering how to do it you can put the denominator in desmos and where the 2 points hit the x axis is your answer.
User Erikw
by
7.7k points
1 vote

Answer:

x=1 and x=2

Explanation:


f(x)=(x-8)/(x^2-3x+2)

To find the vertical asymptote , we set the denominator =0 and solve for x


x^2-3x+2=0

Factor the left hand side of the equation

Product is 2 and sum is -3

the factors are -2 and -1


(x-2)(x-1)=0

Set each factor =0 and solve for x


x-2=0 , x=2


x-1=0 , x=1

the vertical asymptote at x=1 and x=2

User Genma
by
7.6k points