Question

A plane flying horizontally at an altitude of 2 mi and a speed of 510 mi/h passes directly over a radar station. find the rate at which the distance from the plane to the station is increasing when it is 3 mi away from the station. (round your answer to the nearest whole number.)

Answer 1

P is the plane's position

R is the radar station's position

V is the point located vertically of the radar station at the plane's height

h is the plane's height

d is the distance between the plane and the radar station

x is the distance between the plane and the V point

Since the plane flies horizontally, we can conclude that PVR is a right triangle. Therefore, the pythagorean theorem allows us to know that d is calculated:

d=(h^2+x^2)^(1/2)

We are interested in the situation when d=2mi, and, since the plane flies horizontally, we know that h=1mi regardless of the situation.

We are looking for

(dd/dt)=d'.

d^2=h^2+x^2

d'=(x*x')/d

We can calculate that, when d=3mi

x=(d^2−h^2)^(1/2)=(3^2−2^2)^(1/2)=(5)^(1/2) m

Knowing that the plane flies at a constant speed of 510mi/h, we can calculate:

d'=(x*x')/d=(((5)^(1/2))*(510))/3= 380.13 mi/h.

the rate at which the distance from the plane to the station is increasing when it is 3 mi away from the station is 380 mi/h