Question

At standard temperature and pressure (0 ∘c and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 l. what volume would the same amount of gas occupy at the same pressure and 95 ∘c ?

Answer 1

PV=nRT
V=(nRT)/P

95 celsius=368 kelvin

V=(1)(0.0821)(368)/1
=30.22L