Question

18 What is the equation of the line that is perpendicular to y = -x – 10 and contains point (-12, 1)? A y = X - 8 B y = - 15 C y = -x - 8 D y = 3*+ 17​

Answer 1

The equation of the line that is perpendicular to y = -x – 10 and contains point (-12, 1)

`y=x+13`

Please note there is something wrong with the values given question. This is correct answer.

Explanation:

Slope of line y = -x – 10 is m1=-1

Since slope of perpendicular lines are negative reciprocal of each other

Slope of other line is m2=1

Equation of line contains point (-12, 1) and having slope m2=1 is

`y-y_1=m(x-x_1)`

`y-1 = 1(x+12)`

`y =x+12+1 \\y = x + 13`