Question

Consider the reaction of C6H6 + Br2 -------> C6H5Br + HBr

What is the theoretical yield of C6H5Br if 42.1 g of C6H6 react with 71.7 g of Br2?

Answer 1

The theoretical yield of C₆H₅Br = 70.336 g

Further explanation

Given

42.1 g of C₆H₆

71.7 g of Br2

Required

The theoretical yield

Solution

Reaction

C₆H₆ + Br₂ ⇒ C₆H₅Br + HBr

mol C₆H₆ :

= mass : MW C₆H₆

= 42.1 g : 78 g/mol

= 0.54

mol Br₂ :

= 71.7 g : 160 g/mol

= 0.448

Limiting reactant : Br₂(smaller mol)

mol C₆H₅Br based on Br₂ as a limiting reactant = 0.448

Mass C₆H₅Br :

= 0.448 x 157 g/mol

= 70.336 g