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Given that f(x) = x2 − 4x − 3 and g(x) = the quantity of x plus three, over four , solve for f(g(x)) when x = 9.

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f(x) = x2 − 4x − 3
g(x) =(x+3)/4
x=9
f((9+3)/4)) =((9+3)/4)2-4((9+3)/4)-3
=(3)2-4(3)-3
=6-12-3
=-6-3
=-9
f(g(x))=-9
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