Question

Someone help please by providing work and answers please :)

Answer 1

First we gotta use an equation of motion:


`d = ut + (1)/(2) a {t}^(2)`

Our vertical distance d= 100 m, initial vertical speed u = 0 m/s (because velocity is fully horizontal), and vertical acceleration a = 9.8 m/s2 because of gravity. Let's plug it all in!


`100 = 0 + (1)/(2) (9.8) {t}^(2)`

Now we just need to solve for t:


`{t}^(2) = (2(100))/(9.8) \\ \\ t = \sqrt{(2(100))/(9.8)}`

Hit the calculators, and you'll get 4.5 seconds!