Question

A rescue mission has been conducted using a plane to drop supplies in medical personnel. Helicopters also sent from the same station to rescue wanted persons. If a plane flies 400 mph, helicopter flies 200 mph and they leave at the same time, how far away is the rescue site if the helicopter arrives one hour after the plane arrives? If t represents the time that the plane flies which of the following equations would be used to solve the problem?

Answer 1

400t=200(t+1)

Explanation:

• The speed of the plane = 400 mph

,

• The time that the plane flies = t hours

Similarly:

• The speed of the helicopter = 200 mph

Since the helicopter arrives one hour after the plane arrives:

• The time taken by the helicopter = (t+1) hours

`\begin{gathered} Speed=(Distance)/(Time) \\ \implies Distance=Speed* Time \end{gathered}`

The distance covered by the plane = 400t

The distance covered by the helicopter = 200(t+1).

Since both were sent from the same station, it means that the distance covered is the same.

Therefore, the equation that could be used to solve the problem is:

`400t=200(t+1)`

The third option is correct.