Question

URGENT!!! TIMED!!!

A 130-kg football player runs at a speed of 8.0 m/s toward a 110-kg player who is standing still. After the big player tackles the smaller player, they fall together. With what speed do they fall?

Answer 1

v₃ = 4.33 [m/s]

Step-by-step explanation:

This problem can be solved by the conservation of linear momentum, where momentum is preserved before and after the crash or collision.

For this case, the following equation will be constructed. With values before the collision to the left of the equal sign and after the collision to the right of the equal sign.

`(m_(1)*v_(1))+(m_(2)*v_(2))=(m_(1)+m_(2))*v_(3)`

where:

m₁ = mass of the big football player = 130 [kg]

m₂ = mass of the second football player = 110 [kg]

v₁ = velocity of the big football player before the collision = 8 [m/s]

v₂ = velocity of the second football player before the collision = 0 (who is standing still).

v₃ = velocity of the two players after the collision [m/s]

Now replacing:

`(130*8)+(110*0)=(130+110)*v_(3)\\1040 = 240*v_(3)\\v_(3)=4.33[m/s]`