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What is the value of c such that: x^2+14x+c is a perfect-square trinomial?

User Erickg
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2 Answers

2 votes
That value of c would be 49.  To obtain this, take the coefficient (14) of the x term, halve it, and then square the result:  half of 14 is 7, and the square of 7 is 49.
User JaMiT
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5 votes
We are asked to find a value of
c in which the trinomial
x^2+14x+c is a perfect square trinomial. The easiest way to do this is by using a method called completing the square. This method calls for taking half of the
b term and squaring it. In this case, the
b term is 14. When we halve it, we get
14 / 2 = 7. When we square it, we get
7^2=49. Therefore, the value of
c in the trinomial
x^2+14x+c is
\boxed{49}.
User Kingamoon
by
7.0k points
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