Question

⦁ Find the area of a regular Octagon with side lengths 5in. Round your answer to the nearest tenth.

apparently, this is incomplete so there's more to it...someone plz help me
A=2(1+√2)a^2=2*(1+√2)*5^2=120.71068

Answer 1

You forgot to round to the nearest tenth. 120.7

Answer 2

Area of octagon = 120.7
`in^(2)`

Explanation:

We know that,

Area of a regular octagon =
`2 * (1+√(2)) * a^(2)`, where a is the length of the side.

Now, we have a = 5 inches.

Substituting the value of 'a' in the above formula, we have,

Area of a regular octagon =
`2 * (1+√(2)) * 5^(2)`

i.e. Area of a regular octagon =
`50 * (1+√(2))`

i.e. Area of a regular octagon =
`120.71068`

So, we get the area of the octagon is 120.71068
`in^(2)`.

But, it is required to round the answer to the nearest tenth.

Hence, area of the octagon = 120.7
`in^(2)`.