Answer:
If the distance doubles, the gravitational force is divided by 4
Step-by-step explanation:
Newton’s Universal Law of Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
![\displaystyle F=G{\frac {m_(1)m_(2)}{r^(2)}}](https://img.qammunity.org/2022/formulas/physics/high-school/wcewt37keqkx5y5hl8te39qvrou9h1vq1k.png)
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
If the distance between the interacting objects doubles to 2r, the new force F' is:
![\displaystyle F'=G{\frac {m_(1)m_(2)}{(2r)^(2)}}](https://img.qammunity.org/2022/formulas/physics/high-school/furc84g1p9m8292kn7769xijnppcio6ays.png)
Operating:
![\displaystyle F'=(1)/(4)G{\frac {m_(1)m_(2)}{r^(2)}}](https://img.qammunity.org/2022/formulas/physics/high-school/f8umu7wvp54v1t30j28n495rfc9r08oabm.png)
Substituting the original value of F:
![\displaystyle F'=(1)/(4)F](https://img.qammunity.org/2022/formulas/physics/college/7ypbw1x8k3f1smoxi6nnq3lbqel3u5keeo.png)
If the distance doubles, the gravitational force is divided by 4