Question

(HELP PLEASE) if f(x)=x/3-2 and g(x)=3x^2+2x-6 , find (f+g)(x)

Answer 1

Identify and sum up the x^2 terms: Result: 3x^2
Next, ident. and sum up the x terms: Result: (1/3 + 2) = (7/3)x
Last, ident. and sum up the const. terms: Result: -2 - 6 = -8

The sum of these two functions is 3x^2 + (7/3)x - 8.

Answer 2

(A)

Explanation:

The given functions are:

`f(x)=(x)/(3)-2` and
`g(x)=3x^2+2x-6`

Now,
`(f+g)(x)=f(x)+g(x)`

therefore,
`(f+g)(x)=(x)/(3)-2+3x^2+2x-6`

=
`3x^2+2x+(x)/(3)-8`

=
`(9x^2+6x+x-24)/(3)`

=
`(9x^2+7x-24)/(3)`

=
`3x^2+(7)/(3)x-8`

Thus,
`(f+g)(x)=3x^2+(7)/(3)x-8`

Hence, Option A is correct.