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Use the periodic table to determine the number of valence electrons in each of the following elements. Na: F: V: Ar: C:

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1) Sodium (Na) : 1 valence electron.

Sodium (Na) is an element with atomic number 11 and it has one valence electron (3s¹) like all alkaline metals.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

2) Fluorine (F): 7 valence electrons.

Fluorine has atomic number 9, it means it has 9 protons and 9 electrons.

Electron configuration of fluorine: ₉F 1s² 2s² 2p⁵.

3) Vanadium (V): 5 valence electrons.

Vanadium (V) is element with atomic number 23 (23 protons and 23 electrons).

Electron configuration of vanadium atom: ₂₃V 1s² 2s² 2p⁶ 3s² 3p⁶ 3d³ 4s².

4) Argon (Ar): 8 valence electrons.

Atomic number of argon (Ar) is 18, it means that it has 18 protons and 18 electrons.

Electron configuration of argon atom: ₁₈Ar 1s² 2s² 2p⁶ 3s² 3p⁶.

5) Carbon (C): 4 valence electrons.

Electron configuration of carbon atom: ₆C 1s² 2s² 2p².

User Han Parlak
by
7.4k points
3 votes
that correct answers for the question are
Na: 1
F: 7
V: 5
Ar: 8
C: 4

I already took the assignment.
hope it help you.
User Marina Liu
by
7.6k points

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