Question

Two genes of a flower, one controlling blue (b) versus white (b) petals and the other controlling round (r) versus oval (r) stamens, are linked and are 10 map units apart. you cross a homozygous blue-oval plant with a homozygous white-round plant. the resulting f1 progeny are crossed with homozygous white-oval plants, and 1,000 f2 progeny are obtained. how many f2 plants of each of the four phenotypes do you expect? _____ blue-oval : _____ white-round : _____ blue-round : _____ white-oval

Answer 1

The number of F2 plant of each of the four phenotypes that we expect is as follows 450 blue oval: 1 white round:50 blue round :1 white oval. According to the father of genetic that is Mendel F2 generation is obtained after crossing F1 generation

Answer 2

450 = blue-oval

450 = white-round

50 = blue-round

50 = white-oval

Step-by-step explanation:

Blue flower is dominant over white flower

Round stamen is dominant over oval stamen

Parent 1: Blue-oval = BBrr

Parent 2: White-round = bbRR

BBrr X bbRR = BbRr

When BbRr X bbrr ( given that the two genes are 10mu apart which means that recombination frequency is 10% ) =

Br/br = blue-oval = Parental = 45%

bR/br = white-round = Parental = 45%

BR/br = blue-round = Recombinant = 5%

br/br = white-oval = Recombinant = 5%

Hence, out of the 1000 f2 plants,

450 = blue-oval

450 = white-round

50 = blue-round

50 = white-oval