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If henry were to add 5 gallons of water to a tank that is already 34 full of water, the tank would be 78 full. how many gallons of water would the tank hold if it were full?

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Please express those fractions properly: 3/4, 7/8.

Let g be the # of gallons the tank could hold when full.

Then (3/4)n + 5 = (7/8)n.

solving for n: Mult all 3 terms by the LCD (8): 6n + 5(8) = 7n.

Then n=5(8) = 40 (gallons). The tank would hold 40 gallons of water were it full.


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