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In the right △ABC with m∠C = 90°, m∠A = 75°, and AB = 12 cm. Find the area of △ABC.
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In the right △ABC with m∠C = 90°, m∠A = 75°, and AB = 12 cm. Find the area of △ABC.

User Daniel Ralston
by
8.0k points

2 Answers

4 votes

Answer:

18

Explanation:

pog pog pogu

User Justnajm
by
7.8k points
3 votes
sinA=BC/AB =>BC=sin75*12
cosA=AC/AB =>AC=cos75*12
the area is (1/2)AC*AB=(1/2)sin75*12*cos75*12=18
User Nezreli
by
8.3k points
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