Question

10. Write the equation of the line that is parallel tox-3y = 9 and passes through the point (3,-1).​

Answer 1

Equation of the line that is parallel tox-3y = 9 and passes through the point (3,-1) is

`y+1= - (1)/(3) (x-2)`

Explanation:

Slope of line x-3y = 9 is -1/3

Since Parallel lines have same slope. Therefore slope of line passing through the point (3,-1) is also -1/3.

Equation of line in point slope form is given as

`y-y_1=m(x-x_1)` ---------- (1)

Here

`m=-(1)/(3) \ \ and \ \ (x_1, y_1)= (3, -1)`

substituting values in equation (1)

`y+1= - (1)/(3) (x-2)`