Question

You toss a tennis ball straight upward. At the moment it leaves your hand it is at a height of 1.5 m above the ground, and it is moving at a speed of 8.2 m/s.

Answer 1

See below

Step-by-step explanation:

So the tennis ball has traveled 1.1 m after it left your hand....what is its speed then?

df = do + vo t + 1/2 a t^2

df = final position= 1.1 do = original position = 0 vo = 8.2 a = - 9.81

1.1 = 8.2t - 4.95 t^2 Solve for t = .147 s

Vf = vo - at = 8.2 - 9.81 (.147) = 6.76 m/s