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What is the probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner that is divided into 15 equal sectors numbered 1 through 15? Enter your answer, as a simplified fraction, in the boxes.

User S Sharif
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2 Answers

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P(H) = 1/2
P(>6) = 9/15 = 3/5

P(Both H AND >6) = 1/2 * 3/5 = 3/10
User Falyne
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Answer:

The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is
(3)/(10)

Explanation:

To find : What is the probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner that is divided into 15 equal sectors numbered 1 through 15?

Solution :

In flipping a coin outcomes are {H,T} = 2

Favorable outcome of getting head on a coin {H}=1

The probability of flipping heads on a coin is


P(H)=(1)/(2)

Spinner that is divided into 15 equal sectors numbered 1 through 15.

Favorable outcome of getting a number greater than 6 {7,8,9,10,11,12,13,14,15}=9

The probability of spinning a number greater than 6 is


P(S)=(9)/(15)


P(S)=(3)/(5)

Now, The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is given by,


P(H\text{ and } S)=P(H)* P(S)


P(H\text{ and }S)=(1)/(2)*(3)/(5)


P(H\text{ and }S)=(3)/(10)

Therefore, The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is
(3)/(10)

User ProllyGeek
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