Question

If the work done to stretch an ideal spring by 4.0 cm is 6.0J, what is the spring constant (force constant) of this spring?

Answer 1

As AL2006 correctly pointed out the formula is 1/2 kx^2. I was thinking of force and work is the integral of force over the distance applied. So now

`W= (1)/(2)k x^(2)`
and

`(2*6.0)/(0.04^(2) ) = k =7500 (J)/(m^(2))`

Answer 2

Spring constant or the force constant, k = 7500 N/m.

Step-by-step explanation:

Given that,

Energy stored in the spring, E = 6 J

Stretching in the spring, x = 4 cm = 0.04 m

To find,

The spring constant (force constant) of this spring.

Solution,

We know that the work done by the spring when it is stretched is given by :

`W=(1)/(2)kx^2`

k is the spring constant

`k=(2W)/(x^2)`

`k=(2* 6)/((0.04)^2)`

k = 7500 N/m

So, the spring constant (force constant) of this spring is 7500 N/m.