Question

Write an equation of the line that passes through (-1,4) and is perpendicular to the line y=-1/3x+3​

Answer 1

Explanation:

Alternate way of doing this using the point-slope formula.

Since y = -3x + 1 is in y=mx + b format, the slope is -3.

m = -3

The slope of the line perpendicular to y = -3x + 1 must be -(1/-3), or 1/3, since m1 = -1/m2.

Point - slope formula:

y - y1 = m (x - x1).

y - 4 = (1/3) (x - 1)

y - 4 = (1/3)x - 1/3

y = (1/3)x - 1/3 + 4

y = (1/3)x - 1/3 + 12/3

y = (1/3)x + 11/3

Answer 2

y = 3x + 7

Explanation:

If the line is perpendicular to y = -1/3x + 3, then the slope will be the reciprocal of 3.

y = 3x + b

To find b, plug in the known point of (-1, 4)

4 = 3(-1) + b

Solve.

4 = -3 + b

7 = b

Your equation is: y = 3x + 7