Question

Which reaction below represents the second ionization of sr?

a.sr(g) → sr⁺(g) + e⁻
b.sr2⁺(g) + e⁻ → sr⁺(g)
c.sr⁺(g) + e⁻ → sr(g)
d.sr⁻(g) + e⁻ → sr2⁻(g)
e.sr⁺(g) → sr2⁺(g) + e⁻?

Answer 1

e.sr⁺(g) → sr2⁺(g) + e⁻
When remove first electron became Sr⁺, second Sr²⁺.

Answer 2

`Sr^(+) (g)-->Sr^(2+) (g)+e`

Step-by-step explanation:

Ionization is removal of most loosely bound electron from an isolated gaseous atom.

First ionization is the removal from a neutral atom.

The equation for it is

a)
`Sr(g)-->Sr^(+) (g)+e`

Second ionization is the removal from a monopositive ion of the atom.

The equation is:

`Sr^(+) (g)-->Sr^(2+) (g)+e`

In ionization there is no addition of electron thus all other equations are cannot be correct.