Answer is: 10.
pH₁ (pond) = 7,5. Pond is bacic.
pH₂ (pond) = 6,5. Pond is acidic.
c₁( H₃O⁺) = ? concentration of hydronium ion.
c₂ (H₃O⁺) = ?
pH = -log c(H₃O⁺) ⇒ c(H₃O⁺) = 10∧(-pH).
c₁(H₃O⁺) = 10⁻⁷·⁵ = 3,2·10⁻⁸ M(mol/dm³).
c₂(H₃O⁺) = 10⁻⁶·⁵ = 3,2·10⁻⁷ M(mol/dm³).
factor = c₂(H₃O⁺)/ c₁(H₃O⁺) = 3,2·10⁻⁷/3,2·10⁻⁸ = 10 (ten times greater concentration).