Question

write an equation of the line that passes through (-1, 4) and is perpendicular to the line y=-1/3x+3​

Answer 1

y= 3x + 7 Explanation:

y= -1/3x+3 (so, gradient of this line is -1/3).

formula: gradient of line one x gradient of line two= -1 (applies for 2 perpendicular lines only).

So, m1 x -1/3= -1

m1= (
`\frac{-1}{\frac{-1} {3} }`)

m1= 3 (gradient of perp line)

y=mx+c

4= 3 x -1 + c

7=c

therefore, y=3x+7 (eqn of the line perp to y=-1/3x+3)