Question

HELP PLEASE
MATH QUESTION

Answer 1

`\displaystyle 11,7\:cm. ≈ AC`

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`\displaystyle ∠E`

Explanation:

When you draw your triangle, based on the information given to you, you will end up having to use the secant [or cosine] trigonometric ratio. Here is how it is done:

`\displaystyle (14)/(AC) = sec\:33 \hookrightarrow 14 = ACsec\:33 \hookrightarrow (14)/(sec\:33) = AC; 11,741387951... = AC \\ \\ 11,7 ≈ AC`

OR

`\displaystyle (AC)/(14) = cos\:33 \hookrightarrow 14cos\:33 = AC; 11,741387951... = AC \\ \\ 11,7 ≈ AC`

Extended information on trigonometric ratios

`\displaystyle (OPPOCITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOCITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOCITE) = csc\:θ \\ (ADJACENT)/(OPPOCITE) = cot\:θ`

Well, there you have it! With all of this information, you should be capable of understanding the concept.

I am joyous to assist you at any time.