A(-4,-6) ; B(2, 6). Since we know the line crosses A & B, it becomes easy to find its LINEAR equation: y = mx + b
1st calculate the slope m= (y₂ -y₁)/(x₂ -x₁) → m= (6+6)/(2+4) = 12/6 → m =2
2nd Replace in y = mx+b, "m" by 2:
y = 2x+b
3rd to calculate b, replace x and y in y = 2x+b with any coordinate either of A or B. Say we choose B(2,6) → y= 2x + b → 6 = 2(2) + b
6 = 4 + b and b = 2, hence the final equation is:
y = 2x + 2 (in slope intercept value)