The question is incomplete, the complete question is;
Silicon has three naturally occurring isotopes with thefollowing masses and natural abundances:
Isotope Mass ({\rm amu}) Abundance (%)
{\rm Si}-28 27.9769 92.2
{\rm Si}-29 28.9765 4.67
{\rm Si}-30 29.9737 3.10
Calculate the atomic mass of silicon.
Answer:
28.09 amu (to four significant figures)
Step-by-step explanation:
Given that;
Isotope Mass Abundance (%)
Si-28 27.9769 92.2
Si-29 28.9765 4.67
Si-30 29.9737 3.10
So we now have;
Relative atomic mass of silicon;
(27.9769 × 0.9218) + (28.9765 × 0.0471) + (29.9738 × 0.0312)
25.789 + 1.365 + 0.9351 = 28.09 amu (to four significant figures)