Final answer:
The probability of selecting 2 solid chocolates in a row is 9/124.
Step-by-step explanation:
To find the probability of selecting 2 solid chocolates in a row, we need to determine the probability of selecting a solid chocolate as the first piece and then, given that the first piece was solid chocolate, the probability of selecting another solid chocolate as the second piece.
The probability of selecting a solid chocolate as the first piece is 9/32, as there are 9 solid chocolates out of the total 32 chocolates. Once the first solid chocolate is selected, there are 8 solid chocolates remaining out of the total 31 chocolates for the second selection. So, the probability of selecting another solid chocolate as the second piece, given that the first piece was solid chocolate, is 8/31.
To find the probability of both events happening (selecting 2 solid chocolates in a row), we multiply the individual probabilities: (9/32) * (8/31) = 72/992 = 9/124.