Question

How much heat must be removed when 50 grams of steam at 100°C Is condensed to form liquid water at 100°C?

Answer 1

the answer is 113.4 Kj

Step-by-step explanation

Heat is referred to as a form of energy that can be easily achieved by burning fuel, the neat need can be calculated by using the formula:

`\begin{gathered} \\ E=mL \end{gathered}`

where E is the amount of heat(energy)

m is the mass

C is the specific heat capacity of water

T is the temperature

L is (specific heat of vapourisation of steam is 2268 kJ/kg)

Step 1

given

`\begin{gathered} m=\text{ 50 grams=}50\text{ gr\lparen}\frac{1\text{ kg}}{1000\text{ gr}}\text{\rparen=0.05 kg} \\ \end{gathered}`

a)Heat released during conversion of steam at 100°C to water at 100°

`\begin{gathered} E=mL \\ E=0.05kg*2450\text{ Kj/kg} \\ E=122.5\text{ kj} \end{gathered}`

b)heat produced

`\begin{gathered} E=mC(T_(2)-T_(1)) \\ E=0.05Kg*2268(kJ)/(Kg)=113.4\text{ kj} \end{gathered}`

therefore, the answer is 113.4 Kj

I hope this helps you