Question

Voltage drops in a series circuit are added to equal source voltage. Please find the value of E^2 in the volts circuit.

Answer 1

`\begin{gathered} E2=Es-E1-E3-E4 \\ E1=870mV=870x10^(-3)mV=0.87V \\ E2=10V-0.87V-2.73V-3.25V \\ E2=3.15V \\ \text{The E2 is 3.15V} \\ \\ 6) \\ 88MHz=88x10^3KHz=88000KHz \\ 88MHz\text{ is }88000KHz \\ \\ 7)\text{ } \\ 0.56Mohm=0.56x10^3Kohm=560Kohm \\ 0.56Mohm\text{ is }560Kohm \\ \\ 8)\text{ }35,000V=35,000x10^(-6)MV=0.035MV \\ 35,000V\text{ is }0.035MV \end{gathered}`