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Ten beans are lying on a table. Each bean has one different number, 1-10. If you choose a bean with your eyes closed, what is the chance of choosing a prime number ?

Ten beans are lying on a table. Each bean has one different number, 1-10. If you choose a bean with your eyes closed, what is the chance of choosing a prime number ?
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Ten beans are lying on a table. Each bean has one different number, 1-10. If you choose a bean with your eyes closed, what is the chance of choosing a prime number ?

User Deebee
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1 Answer

1 vote
Prime numbers: 2, 3, 5, 7.
There are 4 prime numbers and 10 possibilities, so the probability is 4/10 = 2/5 or 40%
User Yota
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7.8k points
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