114k views
4 votes
If a 990 kg car is on the road and the Ff is 360 N, what is the normal force?

User Yakiang
by
7.8k points

2 Answers

2 votes
Hello,

To find the solution to this question use the normal force formula:

N = mg

Where,

N = normal force

m = weight

g = acceleration of gravity

Therefore:

N = (990 kg) x (9.80 m/s²)

= 9702 N

Thus, the normal force of the car is 9702 N.


Faith xoxo

User Evgen Filatov
by
8.0k points
7 votes

Step-by-step explanation:

It is known that relation between normal force and mass is as follows.

N = m × g

where, N = normal force

m = mass of an object

g = acceleration due to gravity = 9.8
m/s^(2)

And, it is given that mass of the car is 990 kg. Hence, calculate the normal force as follows.

N = m × g

=
990 kg * 9.8 m/s^(2)

= 9702 N

This force will be acting in the upward direction.

Thus, we can conclude that the normal force for given situation is 9702 N.

User Fred Nurk
by
6.8k points