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How will the graph of log x compare to the graph of ln x?

User Latanya
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Both graphs pass through (1,0). Both graphs have an asymptote which is the y axis and the graph drops towards -∞ as x goes from 1 to zero. The graph of log x is shallower (assuming base 10) than ln x. For example log 10 = 1 but ln 10 is about 2.3. This value is constant when comparing the y values for the two functions. Log 100 = 2 but ln 100 = 4.6 which is 2.3 times 2. As x increases the graphs of both functions have a shallower gradient.
User VBart
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Answer and Explanation :

To find : How will the graph of
\log x compare to the graph of
\ln x?

Solution :

We know that,


\log x means the base 10 logarithm.


\ln x means the base e logarithm.

The graph of
\log x and
\ln x touches at point (1,0).

The graph of
\log x is stretched more as x increases, the y values continue to increase.

The graph of
\ln x increases at a faster rate as x increases.

The major difference between them is to be that the y-values in the natural log graph increase at a faster rate than the y-values for the common logarithm graph.

Refer the attached figure below.

How will the graph of log x compare to the graph of ln x?-example-1
User Versatile
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