Question

8u/u^2-18u+81 subtract 72/u^2-18u+81

Answer 1

Your question is:

`(8u)/(u^2-18u+81) -(72)/(u^2-18u+81)`
Then, the above formula equate:


`(8u-72)/(u^2-18u+81)`
Factor out 8 from the numerator we get:

`(u-9)/(u^2-18u+81)`
Factorization of the denominator:

`(u-9)/((u-9)^2)`
Simplifying the numerator and the denominator by (u-9) we get:

`(1)/((u-9))`