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A watering can dispenses water at the rate of 0.25 gallon per minute. The original volume of water in the can was 6 gallons. Which set of ordered pairs shows the volume of water in the can in gallons (y), as a function of time in minutes (x), from the first minute after the can starts dispensing water? (1 point)

User Gre Hahn
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2 Answers

3 votes

Final answer:

The volume of water in the can can be represented as a function of time by the equation y = 6 - 0.25x, where x is the time in minutes and y is the volume of water in gallons.

Step-by-step explanation:

The volume of water in the can can be represented as a function of time by the equation y = 6 - 0.25x, where x is the time in minutes and y is the volume of water in gallons. This is because the original volume of water in the can is 6 gallons, and the can dispenses water at a rate of 0.25 gallon per minute. Therefore, as time increases, the volume of water in the can decreases by 0.25 gallon per minute.

For example, after 1 minute (x = 1), the volume of water in the can would be y = 6 - 0.25(1) = 5.75 gallons.

User Rameshwar Vyevhare
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6.8k points
5 votes
At x=0 y=6 the y intercept. The rate is -0.25 so the equation is y=6-0.25x. The ordered pair is (x,6-0.25x).
User Arul Kumaran
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