A sample of ammonia has a mass of 51 g. How many molecules are in this sample?

asked Jul 12, 2018 125k views

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m(NH₃)=51g, n(NH₃)=m/M=51g÷17g/mol(14+3×1)=3mol
N(NH₃)=n×Na(Avogadro number)=3mol×6·10²³1/mol=18×10²³ molecules

David Lynch answered Jul 19, 2018

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