1 Answer

Rafahoro · Answer 1 · 2018-12-13T11:57:15+0000

A(4,2) to (X + 1, y - 5)
so
A' (5, -3)
then reflected across y-axis
A' (-5, -3)

a)A(4,2), point A is located in quadrant I
b)A'(5,-3), point A' is located in quadrant IV
c)A'(-5,-3), point A' is located in quadrant III

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