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Calculate the number of molecules of hydrogen that are required to completely react with 75.9L of oxygen at STP. The product of this reaction is water. Show all work including balanced equation.

User Simmons
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2 Answers

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= 40,68·10²³ molecules

Hope this helps!
User Scooter Morris
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2H₂ + O₂ = 2H₂O
n(O₂)=V/Vm, V-volume, Vm=22,4 dm³/mol at standard condition.
n(O₂)=75,9 dm³/22,4dm³/mol=3,39 mol
n(O₂):n(H₂)=1:2, n(H₂)=6,78 mol
N=n·Na(Avogadro number), N(H₂)=6,78 mol·6·²³ 1/mol = 40,68·10²³ molecules

User Eugene Tartakovsky
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