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between which two ordered pairs does the graph of f(x) = x2 + x – 9 cross the negative x-axis? quadratic formula: x = (–6, 0) and (–5, 0) (–4, 0) and (–3, 0) (–3, 0) and (–2, 0) (–2, 0) and (–1, 0)
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Dec 8, 2018
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between which two ordered pairs does the graph of f(x) = x2 + x – 9 cross the negative x-axis? quadratic formula: x = (–6, 0) and (–5, 0) (–4, 0) and (–3, 0) (–3, 0) and (–2, 0) (–2, 0) and (–1, 0)
Mathematics
high-school
Rishav Tandon
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i just took the test the answer is A (-6,0) and (-5,0)
Sam Yi
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Dec 10, 2018
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Sam Yi
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The negative root of x^2+x-9=0 is -1/2 - (√37) / 2 ≈ -3.541, so the answer is:
between
(–4, 0) and (–3, 0).
If you don't want to calculate the roots, you can verify that the x-axis is crossed between x=-4 and x=-3 by observing the sign of f change.
f(-4) = 16-4-9 = 3
f(-3) = 9-3-9 = -3
The sign changed (f went from 3 to -3) so it must have crossed the x-axis.
Shibi
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Dec 15, 2018
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Shibi
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