2 Answers

Anetta · Answer 1 · 2018-12-02T13:27:14+0000

product of complex numbers (-3i +4) and (3i +4)

(x - y)(x + y) = x² - y²

(-3i +4)(3i +4) = (4 -3i )(4 + 3i) = 4² - (3i)² = 16 - 9*(-1)=16 + 9 = 25

Ypicard · Answer 2 · 2018-12-07T09:10:19+0000

Answer:

(-3i+4)*(3i+4)=25

Explanation:

1. First writhe the complex numbers to multiply:

(-3i+4)*(3i+4)

2. Multiply the first term of the first parentheses by the first term of the second parentheses:

-3i*3i=-9i^(2)

3. Multiply the first term of the first parentheses by the second term of the second parentheses:

-3i*4=-12i

4. Multiply the second term of the first parentheses by the first term of the second parentheses:

4*3i=12i

5. Multiply the second term of the first parentheses by the second term of the second parentheses:

4*4=16

6. Write all the terms:

(-3i+4)*(3i+4)=-9i^(2)-12i+12i+16

7. Add up the terms:

(-3i+4)*(3i+4)=-9i^(2)+16

8. As
i^(2)=-1 :

$(-3i+4)*(3i+4)=-9(-1)+16\\(-3i+4)*(3i+4)=9+16\\(-3i+4)*(3i+4)=25$

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