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Water can be formed according to the equation: 2h2 (g) + o2 (g) → 2h2o (g) if 8.0 l of hydrogen is reacted at stp, exactly how many liters of oxygen at stp would be needed to allow complete reaction?

User Tanika
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2 Answers

6 votes
Four litre of oxygen will be required
User Daniel Petrov
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8.3k points
0 votes

Answer:

3.99 liters of oxygen at STP would be needed to allow complete reaction.

Step-by-step explanation:


2H_2+2O_2\rightarrow 2H_2O

At STP, 1 mol of gas occupies = 22.4 L

Then 1 Liter of volume will be occupied by:


1 L=(1)/(22.4 ) mol

The 8 Liter of volume will be occupied by:


(1)/(22.4 )* 8 mol=0.3571 mol

Moles of hydrogen gas = 0.3571 mol

According to reaction, 2 moles of hydrogen gas reacts with 1 mol of oxygen gas.

Then 0.3571 moles of hydrogen gas will react with:


(1)/(2)* 0.3571 mol=0.1785 mol of oxygen

Moles of oxygen required to react completely = 0.1785 moles

At STP, 1 mol of gas occupies = 22.4 L

Then 0.1785 moles of oxygen will occupy:


0.1785 moles* 22.4 L = 3.99 L

3.99 liters of oxygen at STP would be needed to allow complete reaction.

User Syllabix
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7.7k points
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