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One drawer in a dresser contains 8 blue socks and 6 white socks. a second drawer contains 3 blue socks and 5 white socks. one sock is chosen from each drawer. what is the probability that they match

2 Answers

3 votes
Drawer 1: P(blue) = 8/14 P(white) = 6/14
Drawer 2: P(blue) = 3/8 P(white) = 5/8

P(blue/blue)=(8)/(14)*(3)/(8)=(3)/(14)

P(white/white)=(6)/(14)*(5)/(8)=(15)/(56)

P(match)=(3)/(14)+(15)/(56)=(27)/(56)
The answer is: 27/56 or as a decimal fraction 0.482 or as a percentage 48.2%.

User Kalyan Halder
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8.1k points
6 votes
The probably would be a chance of matching 74%
User Pahaz
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8.4k points