INFORMATION:
We have the next pairs of atoms:
- Aluminum and oxygen
- Oxygen and strontium
- Nitrogen and sodium
- Bromine and bromine
- Fluorine and francium
And we must put the pairs of atoms in order, with the pair that has the biggest electronegativity difference at the top of the list
STEP BY STEP EXPLANATION:
To order the pairs, we must calculate the electronegativity difference of each pair:
- Aluminum and oxygen:
Electronegativity of first element: 1.61
Electronegativity of second element: 3.44
Electronegativity difference: |1.61 - 3.44| = 1.83
- Oxygen and strontium:
Electronegativity of first element: 3.44
Electronegativity of second element: 0.95
Electronegativity difference: |3.44 - 0.95| = 2.49
- Nitrogen and sodium:
Electronegativity of first element: 3.04
Electronegativity of second element: 0.93
Electronegativity difference: |3.04 - 0.93| = 2.11
- Bromine and bromine:
Electronegativity of first element: 2.96
Electronegativity of second element: 2.96
Electronegativity difference: |2.96 - 2.96| = 0
- Fluorine and francium:
Electronegativity of first element: 3.98
Electronegativity of second element: 0.79
Electronegativity difference: |3.98 - 0.79| = 3.19
Then, the order will be
Fluorine and francium: 3.19
Oxygen and strontium: 2.49
Nitrogen and sodium: 2.11
Aluminum and oxygen: 1.83
Bromine and bromine: 0
ANSWER:
Fluorine and francium
Oxygen and strontium
Nitrogen and sodium
Aluminum and oxygen
Bromine and bromine