Answer:
−2(3x+12y−5−17x−16y+4)
=(−2)(3x+12y+−5+−17x+−16y+4)
=(−2)(3x)+(−2)(12y)+(−2)(−5)+(−2)(−17x)+(−2)(−16y)+(−2)(4)
=−6x−24y+10+34x+32y−8
=28x+8y+2
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