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What is the greatest possible percent error in calculating the volume of a box measured to the nearest inch with sides of 5 in., 10 in., and 10 in.? Round to the nearest percent.
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What is the greatest possible percent error in calculating the volume of a box measured to the nearest inch with sides of 5 in., 10 in., and 10 in.? Round to the nearest percent.

User Raamesh Keerthi
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If each of the side lengths was one inch off, the measurement of the box would be 6*11*11 which would equal 726 inches instead of 500. 500/726≈0.69, so the answer to the nearest percent is 31%. Hope this helps!
User Puja Surya
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