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I’m a group of 55 people 33 are coffee drinkers, 12 are tea drinkers. Assuming that no one in this group drinks both tea and coffee, what is the probability that a person piked random from the group does
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Feb 4, 2018
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I’m a group of 55 people 33 are coffee drinkers, 12 are tea drinkers. Assuming that no one in this group drinks both tea and coffee, what is the probability that a person piked random from the group does not drink tea or coffee
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10/55 of the people do not drink coffee or tea.
Peastman
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Feb 5, 2018
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33+12 = 45 drink either tea or coffee (but not both)
55 - 45 = 10 people drink neither
Divide 10 over 55 and we get 10/55 = 2/11
Use a calculator to find that 2/11 = 0.1818 approximately which converts to 18.18% when you move the decimal point over 2 spots to the right
-------------------------------------------------
Answer as a fraction = 2/11
Answer in decimal form = 0.1818 (approximate)
Answer as a percentage = 18.18% (approximate)
Co Koder
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Feb 10, 2018
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