Question

you (mass 40kg) and a friend (mass 50 kg) are standing on frictionless ice at rest. you oush your friend and he slides to the right with a speed of 4 m/s. what is your speed after the push?

Answer 1

when two objects interact with each other there momentum is unchanged. Therefore,

`m_1v_1=m_2v_2`
`\begin{gathered} 40v_1=50*4_{} \\ 40v_1=200 \\ v_1=(200)/(40) \\ v_1=5m\text{ per seconds} \end{gathered}`