Question

Let be equal 7 , what is the value of the expression 4b^2+b-5?

Answer 1

Answer: 198 (Just took the test and passed)

Step-by-step explanation: order of operation

4b^2+b-5 B=7

4(7^2)+7-5

4(49)+7-5

196+7-5

203-5

198

Answer 2

4(7)^2= 49×4= 196
7-5=2
196+2=198
198 is your answer