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Twice the sum of a number and 7 is equal to 3

User Qinjie
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1 Answer

6 votes
Let n = the number.

Twice the sum of a number and 7 = 3 would be 2(n+7) = 3. Divide by 2 on both sides to get n+7 = 3/2. Then subtract 7 from both sides to isolate the variable n.

n = 3/2 - 7. N = -5.5 or -11/2
User JGrubb
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